(2^x)+(2^2x)=28

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Solution for (2^x)+(2^2x)=28 equation: 



(2^x)+(2^2x)=28

We move all terms to the left:

(2^x)+(2^2x)-(28)=0

We move all terms containing x to the left, all other terms to the right

2^x+2^2x=28

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